Question

1. (section 2.1) Bungee jumping: Jimmy jumped off the Tallahatchie Bridge, 100 ft above

the water, with a bungee cord tied to his legs. If he was 8 ft above the water 5 seconds
after jumping, then what was the average rate of change of his altitude as the time
varied from 0 to 5 seconds?

Answer 1

18.4 ft per second.

Explanation:

Bungee jumped off the Tallahatchie Bridge, which is 100 ft above the water surface.

And after 5 seconds he was at 8 ft above the water surface.

Therefore, in total 5 seconds, he descends by total ( 100 - 8 ) = 92 ft altitude.

Hence, the average rate of change of his altitude is given by

`\frac{\textrm{Total altitude change}}{\textrm{Total time taken}} = (92)/(5) =18.4` feet per seconds. (Answer)