G(x)=27x^3+125 Find factors of the binomial g(x). A. g(x)= (3x+5)(9x^2+15x+25) B. g(x)= (3x-5)(9x^2+15x+25) C. g(x)= (3x+5) (9x^2-15x+25) D. g(x)= (3x-5)(9x^2-15x+25)

Question

asked Dec 10, 2020 72.8k views

1 Answer

Fvu · Answer 1 · 2020-12-17T08:07:45+0000

Answer:

The answer to your question is: (3x + 5)(9x² - 15x + 25)

Explanation:

Data

G(x) = 27x³ + 125

This is a sum of cubes

Process

$\sqrt[3]{27} = 3$

$\sqrt[3]{125} = 5$

27x³ + 125 = (3x)³ + (5)³ = (3x + 5)(9x² - 15x + 25)