Question

A student measures the length of her dress to be 60 inches long but the actual length of her dress is 65 inches long. What is the percent error of this student

Answer 1

8.333% error

Explanation:

using percent error formula

(actual - expected) / expected * 100 %

actual = 65

expected = 60

plug

(65-60)/60 * 100%

= 8.33 %