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(-28n^4 +90n^2 - 50)÷2n^2 -5​

User Aghidini
by
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1 Answer

4 votes

Answer:

14 n² + 10

Explanation:

Given as ( -28n^4 + 90n² -50) ÷ (2n² - 5)

We can solve this by division method,

Now , 14n² × (2 n² -5) = 28 n^4 - 70n²

Or, (-28n^4 + 90n² -50) + (28n^4 -70n²) = 20n² -50

Now again ,

10 ×(2n² -5) = 20n² -50

Or (20n² -50) +(20n² -50) = 0

Hence The quotient thus formed is 14 n² + 10 Answer

User Torrho
by
5.4k points