Answer:
1. 0
2. -1
3. $120
4. $653.25
5. 4ab + 7a - 2b
Explanation:
1. y = 5, z = 0
2z/y = ?
You'll need to substitute the values of y and z in the expression
2z/y
Becomes
2 * 0 / 5
= 0
So, 2z/y equals 0
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2. x = 0, y = -1 z = 7
xz - y²
Substituting the values of x, y and z in the above algebraic expression
xz - y²
Becomes
0*7 - (-1²)
0 - 1
-1
So, xz - y² equals -1
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3. The question falls under SIMPLE INTEREST
The formula is
I = (PRT)/100
Where I represents Interest
P = Principal (Amount Invested)
R = Rate of Interest
T = Time (in years)
From the question,
The interest is unknown ----------------- (To be calculated)
P equals $600
R = 2%
T = 10 years
Substitute these values in the formula above
I = (PRT)/100
Becomes
I = (600 * 2 * 10) / 100
I = 12000/100
I = 120
Result: The interest is $120
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4.
The formula is
I = (PRT)/100
Where I represents Interest
P = Principal (Amount Invested)
R = Rate of Interest
T = Time (in years)
From the question,
The interest is unknown ----------------- (To be calculated)
P equals $13000
R = 6.7%
T = 9 months
Remember that time has to be in years
So, 9 months must be converted to year(s)
If 12 months makes a years
Then 9 months would be 9/12 years
So, T = 9/12 years
T = 0.75 years
Substitute these values in the formula above
I = (PRT)/100
I = (13000 * 6.7 * 0.75) / 100
I = 65325/100
I = 653.25
Result: The interest is $653.25
5. Simplify 4ab - 3bc + 7a - 2b + 3bc
4ab - 3bc + 7a - 2b + 3bc---------------------- Collect like terms
4ab + 7a - 2b + 3bc - 3bc
4ab + 7a - 2b