Question

What is an equation of the line that passes through the point ( 6 , − 1 ) (6,−1) and is parallel to the line x − 3 y = 3 x−3y=3?

Answer 1

y = 1

Explanation:

Passes through (6,-1)(6,-1)

Find the slope (m)

m=(y2 - y1) / (x2 - x1)

m=(-1 - (-1) ) / (6-6)

m= 0

Parallel to x - 3y = 3

-3y = -x +3

y = 1/3 x -1

Equation of the line equation is y - y1 = m ( x - x1 )

y - ( -1 ) = 0 ( x - 6 )

y + 1 = 0

y = 1