Answer:
f(x) = x^3 - 2x^2 - x + 2
Explanation:
since the zeroes are 1,-1, and 2. we can write the function like
f(x) = (x-1)(x+1)(x-2)
f(x) = (x^2-1)(x-2)
f(x) = x^3 -2x^2 -x +2
and it is true that f(0)=2
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