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What is the height after 2 seconds

h - - 16r {}^(2) + 32r + 48


1 Answer

5 votes

Answer:

48

Explanation:

It is given in the question that height of an object from his starting point as a function of time of travel in seconds of the object.

If height is given by h and time of travel is given by r seconds, then the height is given by

h = - 16r² + 32r + 48

Therefore, h after 2 seconds is - 16 (2)² + 32 (2) + 48 = 48.

Since height is positive so, we can conclude that after 2 secs the object will be 48 height above the initial position. (Answer)

User Mark Renouf
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