Question

A stone is dropped from rest from a tall building how fast is the stone moving after 5s

Answer 1

The final velocity is -49.05 meters per second.

Step-by-step explanation:

Let's use an equation of constant acceleration:

`v=v_0+at\\v=v_0-gt\\`

Where a is the acceleration and g is the acceleration caused by gravity.

Since the object is being dropped from rest,
`v_0=0 (m)/(s)`.

We're looking for the speed after 5 seconds, so
`t=5 s`.

`v=(0(m)/(s))-(9.81(m)/(s^(2)))(5s)\\v=-49.05(m)/(s)`

So the final velocity is -49.05 meters per second.