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Please help answer :)-example-1

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Answer:

Explanation:

1. You just plot the points

2. To plot the line you have to find the slope and y-intercept

Slope =
(y_(2)-y_(1)  )/(x_(2)-x_(1)  ) =
(30-15)/(4-2) =
(15)/(2)

Slope =
(15)/(2)

Y-intercept =
y-y_(1)=m(x-x_(1) )

Y-intercept: y - 15 =
(-15)/(2)(x - 2)

y - 15 =
(-15)/(2)x + 15

Add 15 to both sides

y =
(-15)/(2)x + 30 this is the equation of the line.

So you start with the starting point and then the slope!

User Martin Rohwedder
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5.3k points