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I can’t remember how to do this, please help.

I can’t remember how to do this, please help.-example-1

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Answer:

63°

Explanation:

Without a diagram, we have to assume that ray BC lies between BA and BD. Then the angle addition theorem tells you ...

m∠ABC + m∠CBD = m∠ABD

(7x -9°) + (6x +27°) = 96° . . . . . . substitute the given angle measures

13x +18° = 96° . . . . . . . . . . . . . . . simplify

13x = 78° . . . . . . . . . . . . . . . . . . . subtract 18°

x = 78°/13 = 6° . . . . . . . . . . . . . . divide by the coefficient of x

Then the angle of interest is ...

m∠CBD = (6x +27°) = 6(6°) +27° . . . . . substitute the value of x into 6x+27°

m∠CBD = 63°

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