Question

uniform mementum mas is 90g is pivoted at 40cm mark if the metra rula ia in equilibrium with an mark unknown mass m place at the 10cm mark and mass of 73g place at 70cm .ditermine the value of m when mass of an object is always at it center of gravity​

Answer 1

Unknown mass,
`m = 14 \textrm{ g}`

Step-by-step explanation:

From the figure below,

OE is a meter scale with markings in centimeter.

A is the position of unknown mass m, B is the position of 90 g mass, C is the fulcrum, D is the position of mass 73 g.

Length AC = 40 cm, BC = 10 cm, CD = 20 cm

For equilibrium of the meter scale,

Sum of anti-clockwise moments = Sum of clockwise moments

`F_(A)* AC+F_(B)* BC=F_(D)* CD\\m* 40+90*10=73*20\\40m+900=1460\\40m=1460-900\\40m=560\\m=(560)/(40)=14\textrm{ g}`

Therefore,unknown mass is 14 g.