Question

Five times the difference of twice a number and three, decreased by the sum of the number and eight, equals 13.

Answer 1

n= 68/9

Explanation:

The problem would be 5 ( 2n - 3 ) - ( n+ 8) = 13

10n - 15 -n - 40 = 13

9n - 55 =13

9n= 13+55

9n= 68

( divide both numbers by nine)

n = 68/9