Question

Using the chemical equation in Question 1 above, if 42.6 g of H2 reacts in excess nitrogen gas and the actual yield of NH3 was 200 g, calculate the percent yield of the reaction. Hint: You'll need to calculate the theoretical yield, in g, of NH3 first.

Answer 1

The answer is 82.9%

Answer 2

The answer to your question is: 82.9 %

Step-by-step explanation:

Data

H2 = 42.6 g

NH3 = 200 g

percent yield = ?

Reaction

3H2 + N2 ⇒ 2NH3

Process

6 g of H --------------- 34 g of N

42.6 g ------------- x

x = 241.4 g of NH3

percent yield = 200 / 241.4 x 100

= 82.9 %