Answer:
Part a) Exactly values
The width of the rectangle is
![(√(70))/(2)\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/za85o8m2sngl4aus7r3wqiqoux7v5rsbqp.png)
The length of the rectangle is
![2√(70)\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/880ycil2kx79wtw0x7q5e8en5cfcnzc7li.png)
Part b) Approximately values
The width of the rectangle is
![4.2\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/chsazod61lvnu3o8jfcwmdwfhltjfhk4ai.png)
The length of the rectangle is
![16.7\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/paso9z864y37nornepj0s5wmhhyb4qkdhy.png)
Explanation:
see the attached figure to better understand the problem
we know that
The area of rectangle is equal to
![A=LW](https://img.qammunity.org/2020/formulas/mathematics/high-school/3j0ob8ofk1s943d3rmpkx8tdoddrtl3gew.png)
we have
![L=4x\ cm\\W=x\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uj85wef5jn3ola6h2cqrq15aomxsc4wvo8.png)
substitute the values in the formula
![A=4x(x)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d5bdjpzm7jzuff9mo7o1onjpomnfximaml.png)
![A=4x^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/njx4szwju2kr4111ragyke9w943ac4sab2.png)
![A=70\ cm^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/k53glhmp3w90lh8pcqmqqiyij8u890t2vf.png)
so
![70=4x^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/sqsu70bsfdzx70qe0hk49lfjak4pmuipp0.png)
Solve for x
Divide by 4 both sides
![(70)/(4)=x^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/5wzomqsp0wy30du08z2vq78g239spm0bih.png)
square root both sides
![x=(+/-)(√(70))/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wh7ioy98s72zhia5sfccagez6bzoq1sahw.png)
The solution is the positive value
![x=(√(70))/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1er4buywkk2jkafz1ski90wy0g4a3kmk85.png)
therefore
Exactly values
![L=4√(70)}{2}=2√(70)\ cm\\\\W=(√(70))/(2)\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uhkypipb8fyuhrdpct5y20ve7xmduths7t.png)
Approximately values
![L=4√(70)}{2}=16.7\ cm\\\\W=(√(70))/(2)=4.2\ cm](https://img.qammunity.org/2020/formulas/mathematics/middle-school/oxdcphc5jzvl2p42c04xizhirf4in3621d.png)