Solve the equation log^7b>2

Question

asked Sep 12, 2020 46.1k views

1 Answer

Lakeia · Answer 1 · 2020-09-19T01:32:31+0000

Answer:

b > 12.71

Explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is
$(\log b)^(7) > 2$

⇒
$\log b > 2^{(1)/(7) }$

We are taking the base of the log here is 10.

So,
$10^((\log b)) > 10^{2^{(1)/(7) } }$ {Since
$10^(\log x) =x$ and
$e^(\ln x) = x$ }

⇒ b > 12.71 (Approximate) (Answer)