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Solve the equation log^7b>2

User Jimjamslam
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1 Answer

2 votes

Answer:

b > 12.71

Explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is
(\log b)^(7) > 2


\log b > 2^{(1)/(7) }

We are taking the base of the log here is 10.

So,
10^((\log b)) > 10^{2^{(1)/(7) } } {Since
10^(\log x) =x and
e^(\ln x) = x}

⇒ b > 12.71 (Approximate) (Answer)

User Lakeia
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