Answer:
Sanjay calculation of Train speed is more than Marcus calculation of Train speed
Explanation:
Given in question as
Marcus want to calculate Train speed , covering distance of 0.5 mile in 6 min
Now as we know that Speed =
![(Distance)/(Time)](https://img.qammunity.org/2020/formulas/mathematics/college/celd9v81qwv4b5nwmu15b28jymknh7z8l5.png)
Let take this as S1 =
![(D1)/(T1)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wusqlzk9bdm1502gd96m9yawhszkc0lo7r.png)
S1 =
mile per min
S1 =
mile per hour
Note 1 hour = 60 min
So, S1 = 5 mile per hour
Now , Sanjay want to calculate the Train speed , covering distance of 6 mile in 0.5 hour
Let take S2 =
![(SD2)/(T2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ctx44b9el07x0exqotwxl2xl6i643j9vyz.png)
S2 =
![(6)/(0.5)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ofj3pq3jbrd34lkvxyp6y5kx2l52rva61n.png)
S2 = 12 mile per hour
Hence We can say that Sanjay calculate more Train speed than Marcus .
Answer