206k views
22 votes
What is the ionic equation for the following

2FeCl(aq)
3Mg(s)
3MgCl(aq)
2Fe(s)

What is the ionic equation for the following 2FeCl(aq) 3Mg(s) 3MgCl(aq) 2Fe(s)-example-1
User Wilson Wu
by
5.9k points

1 Answer

6 votes

Answer : The net ionic equation will be,


2Fe^(3+)(aq)+3Mg(s)\rightarrow 3Mg^(2+)(aq)+2Fe(s)

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

The given balanced ionic equation will be,


2FeCl_3(aq)+3Mg(s)\rightarrow 3MgCl_2(aq)+2Fe(s)

The ionic equation in separated aqueous solution will be,


2Fe^(3+)(aq)+6Cl^(-)(aq)+3Mg(s)\rightarrow 3Mg^(2+)(aq)+6Cl^(-)(aq)+2Fe(s)

In this equation,
Cl^(-) is the spectator ion.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,


2Fe^(3+)(aq)+3Mg(s)\rightarrow 3Mg^(2+)(aq)+2Fe(s)

User Danny Parker
by
5.1k points