Answer:
3 burgers and 2 Nachos or
2 burgers and 4 Nachos.
Explanation:
a.)Define variables;
Let n represent Nachos
and b represent burgers
b. System of inequality;
2n+4b ≤ 16
n+b ≥ 5
c. Give 2 possible solutions;
First, using the inequalities above, solve for n;
n ≥ 5-b, then replace n with (5-b) in the second equation;
2(5-b)+4b ≤ 16
10-2b+4b ≤ 16
2b ≤ 16-10
2b ≤ 6
b ≤ 3
Using 3 for b, solve for n;
n+3 ≥ 5
n ≥ 5-3
n ≥ 2
Therefore, one possible solution is ; 3 burgers and 2 Nachos
The second solution can be found this way;
If b=2 use equation 2n+4b ≤ 16 to solve for n;
2n+(2*4) = 16
2n+8= 16
2n=16-8
2n=8
n=4
Therefore second solution is 2 burgers and 4 Nachos.