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a sled starts from rest, and slides down a 38.0° fricionless hill for 4.24s. How fast is it going at the end?​

1 Answer

2 votes

Answer:

The Sled goes fast at 25.60 m/s

Step-by-step explanation:

According to fundamentals, velocity of any body is equal to the product of its acceleration and time period that is,

velocity = acceleration x time ;

According to question a sled starts from rest and slides down a
38.0^(\circ) hill and the time taken to happen so is 4.24s

we have, acceleration =
\mathrm{g} \sin \theta

therefore acceleration = 9.81
\sin 38^(\circ)

= 6.039
(m)/(s^(2)) for the case under consideration;

hence the velocity may be obtained as v=6.039x4.24 = 25.60 m/s

User Peter Schmitz
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