Question

a sled starts from rest, and slides down a 38.0° fricionless hill for 4.24s. How fast is it going at the end?​

Answer 1

The Sled goes fast at 25.60 m/s

Step-by-step explanation:

According to fundamentals, velocity of any body is equal to the product of its acceleration and time period that is,

velocity = acceleration x time ;

According to question a sled starts from rest and slides down a
`38.0^(\circ)` hill and the time taken to happen so is 4.24s

we have, acceleration =
`\mathrm{g} \sin \theta`

therefore acceleration = 9.81
`\sin 38^(\circ)`

= 6.039
`(m)/(s^(2))` for the case under consideration;

hence the velocity may be obtained as v=6.039x4.24 = 25.60 m/s