Question

Will someone help me with this please!!! I don’t know how to find the answer!

Answer 1

`x=4` or
`x=-1.33`

Step-by-step explanation:

From the triangle shown,

EG = DG

Plug in
`3x^(2) -8x` for EG and 16 for DG. Solve for x.

`3x^(2) -8x=16\\3x^(2) -8x-16=0`

The above equation is a quadratic equation of the form
`ax^(2) +bx+c=0` with a = 3, b = -8 and c = -16.

Now, using the quadratic formula, we solve for x.

`x=(-b)/(2a)` ±
`\frac{\sqrt{b^(2)-4ac } }{2a}`

Plug in 3 for a, -8 for b and -16 for c.

`x=(-(-8))/(2(3))` ±
`\frac{\sqrt{(-8)^(2)-4(3)(-16) } }{2(3)}`

`x=(4)/(3)` ±
`(√(256) )/(6)`

`x=(4)/(3)` ±
`(8)/(3)`

`x=(4)/(3)+(8)/(3)=4` or

`x=(4)/(3)-(8)/(3)=-1.33`

Therefore, possible values of
`x` are -1.33 or 4.