Answer:
1/16 th of the previous gravitational force
Step-by-step explanation:
F =G (m1 x m2)/ r^2
r= distance between moon and planet
if r1 = 1 and r2= 4 1^2 / 4^2= 1/16
Fg = (G * m1 * m2) / r^2
The gravitational force is Fg/16
Fg = (G * m1 * m2) / (4r)^2
Fg = (G * m1 * m2) / 16r
Therefore,
Fg / 16
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