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A line that includes the point (-1,6) has a slope of -3. What is its equation in slope-intercept form?

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Answer:

y = -3x + 3

Explanation:

The slope-intercept form of an equation of a line:


y=mx+b

m - slope

b - y-intercept

We have the slope m = -3 and the point (-1, 6) → x = -1, y = 6.

Substitute:


6=(-3)(-1)+b


6=3+b subtract 3 from both sides


6-3=3-3+b


3=b\to b=3

Finally:


y=-3x+3

User Jabamataro
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