Question

How many H atoms are in 72.5 g of C3H2O ?

Answer 1

`\large { \boxed{ 1.62 * 10^(-24) \text{ H atoms}}}`

Step-by-step explanation:

1. Calculate the moles of C₃H₂O

Moles of C₃H₂O = 72.5 g C₃H₂O × (1 mol C₃H₂O /54.05 g C₃H₂O)

= 1.341 mol C₃H₂O

2. Calculate the molecules of C₃H₂O

6.022 × 10²³ molecules C₃H₂O = 1 mol C₃H₂O

Molecules of C₃H₂O

= 1.341 mol C₃H₂O × (6.022 × 10²³ molecules C₃H₂O /1 mol C₃H₂O)

= 8.08 × 10²³ molecules C₃H₂O

3. Calculate the number of H atoms.

There are two H atoms in one molecule of C₃H₂O

`\rm\text{No. of H atoms} = 8.08 * 10^(23)\, molecules\, C_(3)H_(2)O * \frac{\text{2 atoms H}}{\rm 1\, molecule \, C_(3)H_(2)O} = \text{1.62$* 10^(-24)$ H atoms}\\\\\text{There are $\large { \boxed{\mathbf{1.62*10^(-24)}\textbf{ H atoms}}}$} \text{ in the sample}`