Question

What is the mass in grams of KBr in 0.400 L of a 0.350 M solution???

Answer 1

The answer to your question is: 16.7 g of KBr

Step-by-step explanation:

Data

mass KBr = ? g

Volume = 0.400 L

Concentration = 0.350 M

Formula

Molarity = moles / volume

moles = molarity x volume

Process

moles = (0.350)(0.400)

= 0.14

MW KBr = 39 + 80 = 119 g

119 g of KBr -------------------- 1 mol

x -------------------- 0.14 mol

x = (0.14 x 119) / 1

x = 16.7 g of KBr

Answer 2

Answer: It is 16.7

Explanation: (0.400 L) x (0.350 mol/L) x (119.0023 g KBr/mol) = 16.7 g KBr