Question

the temperature of a gas is raised from 10 to 20 degree celsius. Will the volume double the pressure if mass and pressure do not change? Why or why not? show calculations

Answer 1

There will be No change in volume.

Step-by-step explanation:

Ideal Gas Equation is used to solve this :

PV=nRT;

P is pressure in Pa,

V is volume in
`m^3`,

n is number of moles of gas;

R is the universal gas constant, 8.31 J/K mol

T is temperature in Kelvin

when mass is said to be fixed, the number of moles will also be fixed, too. So combining both the constant term n and R which gives

PV=kT

where k is constant.

V=
`(k T)/(P)`

So the equation represents that, Volume V will remains unchanged when pressure and temperature are both doubled, therefore the numerator term T and the denominator term P are both gets affected by multiplication of 2, hence by cancellations:

V =
`\mathrm{k} (T * 2)/(P * 2)`=
`(k T)/(P)`