Question

In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays.Find the probability that he did not hit a boundary. ​

Answer 1

The probability of NOT hitting a boundary is (4/5).

Explanation:

Let E: Be the event of hitting a boundary

now, Probability of any event E =
`\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}`

Here, number of favorable outcomes = 6

So, P(E) =
`(6)/(30)  = (1)/(5)`

⇒Probability of hitting a six is 1/5

Now, P(E) + P(not E) = 1

So, P(not hitting a boundary ) = 1 - P(hitting a boundary)

= 1 - (1/5) = 4/5

Hence, the probability of NOT hitting a boundary is (4/5).