Question

Jessica had a bag of candies. She gave 1/8 of her candies to judy. Then jessica gave 3/7 of the candies she had left to Reggie. Then she lost 75% of what she had left. After all this, Jessica only had 4 candies left. How many candies did Jessica have at the beginning? Pls help

Answer 1

Jessica had 32 candies at the beginning.

Explanation:

Let the number of candies Jessica had at the beginning be
`x`.

Candies gives to Judy =
`(1)/(8)x`.

Now, candies left with Jessica is
`x-(1)/(8)x=(7x)/(8)`.

Candies given to Reggie is
`(3)/(7)` of
`(7x)/(8)`.

∴ Candies with Reggie is
`(3)/(7)*(7x)/(8)=(3x)/(8)`.

Candies left with Jessica after giving to Reggie =
`(7x)/(8)-(3x)/(8)=(4x)/(8)`.

Now, Jessica lost 75% of what she had left. So, 75% of
`(4x)/(8)`.

∴ Candies lost =
`(75)/(100)*(4x)/(8)= (3x)/(8)`

Now, candies left with Jessica =
`(4x)/(8)-(3x)/(8)=(x)/(8)`.

As per question,

Candies left with Jessica at last is 4. So,

`(x)/(8)=4`

`x=32`

Hence, Jessica had 32 candies at the beginning.