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Tyler has some pennies and some nickels. He has no less than 15 coins worth at most

$0.55 combined. If Tyler has 7 pennies, determine the maximum number of nickels
that he could have. If there are no possible solutions, submit an empty answer.​

User Msiyer
by
8.1k points

2 Answers

3 votes

Answer:

9

Explanation:

at most he can use 9 nickels to get the answer

User Mathieu De Brito
by
7.8k points
3 votes

Answer: He only can have 9 nickels.

Explanation:

Let's define P as the number of pennies and N as the number of nickels.

P + N > 15

because he has no less than 15 coins in total.

and:

P*$0.01 + N*$0.05 ≥ $0.55

Because he has at most, $0.55

Now, if P = 7

Now we need to solve:

7*$0.01 + N*$0.05 ≥ $0.55

N*$0.05 ≥ $0.55 - $0.07 = $0.48

Now, with the equality of this relation, we can find the maximal value of N.

N*$0.05 = $0.48

N = 0.48/0.05 = 9.6

So the maximum number of nickels he can have is 9.6, but he can not have a 0.6 of a nickel, so we need to round down to 9.

Now, we also know that he no less than 15 coins in total, with that equation we can find the minimal value of N.

7 + N > 15.

N > 15 - 7 = 8

So we have the range:

8 < N ≤ 9

This means that the only possible value of N is 9

User Kabeer Jaffri
by
8.5k points

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