Answer with explanation:
Let
be the population mean.
As per given we have,
, since alternative hypothesis is right tailed , so the test is a right-tailed test.
Test statistic :

For, n=80
, we have

Critical z-value at
=1.645
Since the test statistic value is greater than the critical z-value, so we reject the null hypothesis, i.e. alternative hypothesis is accepted.
Conclusion: We have enough evidence to support the claim that the mean work week has increased for women at the 5% level.