Question

Solve y = f(x) = (2x+1)^1/2

& g(x) = x-1

Answer 1

f(x) =
`x = (y^(2) - 1)/(2)`

g(x) = 1

Explanation:

y = (2x + 1)^1/2

`y^(2) = 2x + 1`

`y^(2) - 1 = 2x`

`(y^(2) - 1)/(2) = x`

y = x - 1

y + 1 = x