Question

|| Two children fight over a 200 g stuffed bear. The 25 kg boy pulls to the right with a 15 N force and the 20 kg girl pulls to the left with a 17 N force. Ignore all other forces on the bear (such as its weight). a. At this instant, can you say what the velocity of the bear is? If so, what are the magnitude and direction of the velocity? b. At this instant, can you say what the acceleration of the bear is? If so, what are the magnitude Knight, Randall D., (Professor Emeritus). College Physics (p. 130). Pearson Education. Kindle Edition.

Answer 1

No

10 m/s² towards the left

Step-by-step explanation:

Taking right side as positive

`F_(net)=15-17=-2\ N`

`F=ma\\\Rightarrow a=(F)/(m)\\\Rightarrow a=(-2)/(0.2)\\\Rightarrow a=-10\ m/s^2`

The acceleration is 10 m/s² towards the left.

`v=u+at`

`s=ut+(1)/(2)at^2`

`v^2-u^2=2as`

From the three equations of motion it can be seen that in order to find velocity either time or displacement is required. Hence, the velocity cannot be found.