Question

) A 0.30-kg block of wood is suspended on a spring. In equilibrium the wood stretches the spring 2.0 cm downward. The wood is then pulled an additional distance of 1.0 cm down and released from rest. (a) How long does it take the wood to make 3 complete cycles of vibration

Answer 1

`t = 0.85 s`

Step-by-step explanation:

As we know that the block of wood is suspended by spring

Now at equilibrium position we have net force balanced on it

so we have

`mg = kx`

`0.30 * 9.81 = k(0.02)`

so we will have

`k = 147.15 N/m`

now the time period of the spring block system for one complete oscillation is given as

`T = 2\pi \sqrt{(m)/(k)}`

now plug in all values in it

`T = 2\pi \sqrt{(0.30)/(147.15)}`

`T = 0.28 s`

Now total time to complete 3 cycles is given as

`t = 3T`

`t = 0.85 s`