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Find the x-intercept and the y-intercept of the graph of the equation 9x + 16y = 17. Then graph the equation.

2 Answers

2 votes

Answer:

x-intercept = 17/9

y-intercept = 17/16

Explanation:

rearranging the given equation to


9x+16y-17=0

then using the straight line equation


y=mx+c

calculating the y-intercept when x=0, y is 17/16 the line cuts y-axis at y=1.06250


y-intercept =17/16=1.06250

calculating the x-intercept when y=0 the value of x is 17/9 therefore cuts the x-axis at 1.88889


x-intercept=17/9=1.88889

Find the x-intercept and the y-intercept of the graph of the equation 9x + 16y = 17. Then-example-1
User Abraham Duran
by
7.7k points
5 votes

Answer:


(17)/(16)

Explanation:

To calculate the y-incercept, it's easier if we have the formula written like this:


y=ax+b

Where "b" represents the y-incercept.

So we have to isolate Y from the equation:


9x+16y=17\\16y=17-9x\\y=(17-9x)/(16) \\y=(17)/(16) -(9)/(16)x

The y-intercept is the number that doesn't have X ("b"), so in this case the y-intercept is:
(17)/(16)

User Riah
by
8.8k points

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