Question

The potential difference between the plates of a parallel plate capacitor is 35 V and the electric field between the plates has a strength of 750 V/m. If the plate area is 4.0 Ý 10-2 m2, what is the capacitance of this capacitor?

a. 7.6 Ý 10-14 F
b. 7.6 Ý 10-10 F
c. 7.6 Ý 10-11 F
d. 7.6 Ý 10-12 F
e. None of the other choices is correct.

Answer 1

Capacitance will be
`7.6* 10^(-12)F`

So option (d) will be correct option

Step-by-step explanation:

We have given potential difference across the plate V = 35 volt

Electric field between the plate E = 750 volt/m

Area of the plate
`a=4* 10^(-2)m^2`

We have to find the capacitance

We know that potential difference is given by

`V=Ed` here E is electric field and d is distance between the plate

So
`35=75* d`

d = 00466 m

We know that capacitance is given by

`C=(\epsilon _0A)/(d)=(8.85* 10^(-12)* 4* 10^(-2))/(0.0466)=7.6* 10^(-12)F`

So option (d) will be correct option