Question

A balloon filled with helium gas at 20 °C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, raising the pressure to 5.20 atm. What is the volume of the balloon in the liquid nitrogen?

A) 0.25 L
B) 3.6 L
C) 6.7 L
D) 97 L

Answer 1

(A)0.25L

Step-by-step explanation:

By combination of Boyle's law and Charles law to obtain the general gas equation, we have:

P1V1/T1=P2V2/T2

P1=Inital pressure=1.00 atm

V1=Inital volume=4.91L

T1=Initial temperature=20°C=20+273=293Kelvin

P2=Final pressure=5.2atm

T2=Final temperature=(-196+273K)=77K

V2= final volume=?

by making V2 the subject of the above general gas equation

we have V2=P1V1T2/P2T1

=1×4.91×77/5.2×293

=0.248L