Answer:
3.) 463 J/g
Step-by-step explanation:
Heat given by the fuel is used to increase the temperature of the water
so it is given as
![Q = ms\Delta T](https://img.qammunity.org/2020/formulas/physics/middle-school/aaojl4max645uc8q0wgmab8qye2npoievb.png)
here we will have
m = 250 g
![\Delta T = 26.55 - 25](https://img.qammunity.org/2020/formulas/physics/high-school/7gby3ju1nckz7nkmovk58qdb6wu0f3ao15.png)
now we also know that
![s = 4186](https://img.qammunity.org/2020/formulas/physics/high-school/qalh97fs6x57kbgdlve1gobpy8z7epdjuz.png)
so we have
![Q = (0.250)(4186)(26.55 - 25)](https://img.qammunity.org/2020/formulas/physics/high-school/3uraaacjxikca4iiagyxd6eu3h9eplifu5.png)
![Q = 1622.075 J](https://img.qammunity.org/2020/formulas/physics/high-school/f91bwpnyds4hwwmhhr92fex11hvrjii8v4.png)
so 3.5 g fuel gives above energy
so per gram of fuel will have total energy given as
![Q = (1622.075)/(3.5)](https://img.qammunity.org/2020/formulas/physics/high-school/bg2b6nyialaddu85x8nzii1dd4mgxad6xb.png)
![Q = 463.45 J/g](https://img.qammunity.org/2020/formulas/physics/high-school/d03ii1u11orn15gm5mllo66ab38uvunnwb.png)