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A long piece of wood of length 2.8 m is broken into 4 pieces with two pieces of length a and the other two pieces of length b. The four pieces are put together to form a rectangle. Find b if your aim is to have a rectangle with the maximum area.

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Answer:

b = 0.7 m

Step-by-step explanation:

Total length of the wooden rod is given as

[Tex]2a + 2b = 2.8 m[/tex]

so we will have


a + b = 1.4

now we will have


Area = ab

so we have


A = a(1.4 - a)

now to find the maximum area


(dA)/(da) = 0


(dA)/(da) = 1.4 - 2a = 0


a = 0.7 m


b = 0.7 m

User Ruslan Kiskinov
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