Answer:
3.0 seconds
Step-by-step explanation:
The time of flight of a projectile (the time it takes to reach the ground) does not depend on the horizontal motion, but only on its vertical motion.
In fact, the time of flight is determined by the suvat equation:
![s=ut+(1)/(2)gt^2](https://img.qammunity.org/2020/formulas/physics/middle-school/haq562oxtydcq7qnnxcz2vtg34ztzklqnp.png)
where
s is the vertical displacement
u is the initial vertical velocity (0, in case of these two projectiles)
g = 9.8 m/s^2 is the acceleration of gravity (assuming downward as positive direction)
t is the time of flight
Re-arranging the equation, we get
![t=\sqrt{(2s)/(g)}](https://img.qammunity.org/2020/formulas/physics/middle-school/axk5fd6tjehokf94cfvx5y5wj7vf263287.png)
We see that this time depends only on s (the heigth of the cliff) and g: therefore, since the two projectiles are launched from the same height, they take the same time to reach the ground, 3.0 seconds.