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a standing wave in a pipe with both ends open has a frequency of 348. hz. the next higher harmonic has a frequency of 522. hz.

User Seeker
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13 votes

Answer:

A pipe open at both ends would have an antinode at each end and its length would be λ/ 2

The next such points would be λ and 3 λ / 2

The ratio of 522 / 348 is 1.5 so the harmonic at 348 is one wavelength and the next harmonic is 3 λ / 2 at 1 1/2 wavelengths

348 hz would occur at one wavelength

f λ = v = f L where the length of the pipe is one wavelength

if we use 331 as the speed of sound then

L = 331 / 348 = .95 m for the length of the pipe

User Raoul George
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