Answer:
The cone'll require about 37.5 cm of tubing
Explanation:
To do this, we need to know that the volume of the medium will have to be the same volume of the cone that will be printed.
Then, the volume of the cone is:
V = π*r^2*h/3
V = 3.14 * 5^2*8 / 3 = 209.33 cm^3
We can assume that the tubing is a cylinder so:
V = π*r^2*h
The radius is 1 1/3, and this is:
1*3 + 1 = 4/3
Solving for h we have:
h= V/π*r^2
h = 209.33 / 3.14*(4/3)^2
h = 209.33 / 5.58
h = 37.5 cm