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Factor completely.

m 4 - n 4
(m2 - n2)(m + n)(m - n)
(m2 + n2)(m + n)(m - n)
(m2 + n2)(m - n)2

User Klaudio
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2 Answers

5 votes

Answer:

THE 3 one is your answer!!

User Volodymyr Khmil
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2 votes

Answer:

(m - n) (m + n) (m^2 + n^2)

Explanation:

Factor the following:

m^4 - n^4

m^4 - n^4 = (m^2)^2 - (n^2)^2:

(m^2)^2 - (n^2)^2

Factor the difference of two squares. (m^2)^2 - (n^2)^2 = (m^2 - n^2) (m^2 + n^2):

(m^2 - n^2) (m^2 + n^2)

Factor the difference of two squares. m^2 - n^2 = (m - n) (m + n):

Answer: (m - n) (m + n) (m^2 + n^2)

User Daryl Ginn
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