Question

A shopper pushes a cart 29 m south down one aisle and then turns 90.0° west and moves 29 m. He then makes another 90.0° turn and moves 14 m. (a) What is the largest possible displacement of the shopper?

Answer 1

`d = 51.86 m`

Step-by-step explanation:

For largest possible displacement we can say that it must move towards south after it turns 90 degree at the end

So we will have

`x_1 = 29 m` South

`y_1 = 29 m` West

`x_2 = 14 m` South

so total displacement towards South

`x = x_1 + x_2 = 29 + 14`

`x = 43 m`

so net maximum displacement will be

`d = √(x^2 + y^2)`

`d = √(43^2 + 29^2)`

`d = 51.86 m`