Question

Use the discriminant to determine the number of solutions.

6. 4x² + 4x-1
a. 2 reals b. 1 real c. O reals d. 4 reals

Answer 1

one real solution

Explanation:

Let's recall that for the general quadratic expression:
`ax^2+bx+c`, the discriminant is defined as:
`b^2-4*a*c` (which is the expression that appears inside the square root when solving for the solutions of the quadratic equation:
`ax^2+bx+c=0`

In our case, the determinant for
`4x^2+4x+1` can therefore be written as:
`4^2-4*(4)*(1)=16-16=0` therefore this corresponds to only one real solution for the associated equation:
`4x^2+4x+1=0`