Question

An object initially traveling at a velocity of 52 m/s experiences an acceleration of 9.8 m/s^2 how much time will it take to come to rest

Answer 1

5.3 seconds

Step-by-step explanation:

Vx = Vx0 + Ax .T

A= de-acceleration

Vx =0 final at rest velocity

Vx0 = initial velocity

T= time to bring the object to a stop

therefore

0 = 52 m/s - (9.8 m/s^2) . T

-52 m/s/ -9.8 m/sec^2 =T

5.3 seconds= T