Question

A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising the helicopter. An 700-kg helicopter rises from rest to a speed of 11.0 m/s in a time of 3.0 s. During this time it climbs to a height of 9.6 m. What is the average power generated by the lifting force?

Answer 1

`P = 36068.7 Watt`

Step-by-step explanation:

As we know that average power is the ratio of total work done and total time interval

so we will have

`Power = (Total \: Work)/(time)`

now we know that

`Work = (1)/(2)mv^2 + mgh`

`W = (1)/(2)(700)(11^2) + 700(9.8)(9.6)`

so we will have

`W = 42350 J + 68856 J`

`W = 108206 J`

now power is given as

`P = (108206)/(3)`

`P = 36068.7 Watt`