Answer:
x = -1 ± 2i
Explanation:
The standard form of a quadratic equation is ax² + bx + c = 0, and the quadratic formula is x= [−b ± √(b ² - 4ac) ] / 2a
In this case, a = 1, b = 2 and c = 5. Now you have to substitute in the quadratic formula:
x= [−b ± √(b ² - 4ac) ] / 2a
x= [−2 ± √(2 ² - 4*1*5) ] / 2*1
x= [−2 ± √(4 - 20) ] / 2
x= [−2 ± √(-16) ] / 2
Since the square root is negative, you have to use imaginary numbers to continue solving the equation. Remmber that √(-1) = i.
x= [−2 ± √(-16) ] / 2
x= [−2 ± √(16)i ] / 2
x= [−2 ± 4i ] / 2
x1 = [−2 + 4i ] / 2
x1 = -1 + 2i
x2 = [−2 - 4i ] / 2
x2 = -1 - 2i
So the answers of x are -1 ± 2i