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Given: ΔABC; a= 10; b = 13, and ∠C = 70°. Find the length of side c to the nearest whole number

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Answer:


c=13\ units

Explanation:

we know that

Applying the law of cosines


c^2=a^2+b^2-2(a)(b)cos(C)

we have


a=10\ units\\b=13\ units\\C=70\°

substitute


c^2=10^2+13^2-2(10)(13)cos(70\°)


c^2=180.07


c=13\ units

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