Answer:
0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00
Explanation:
Mean =
![\mu = 15.50](https://img.qammunity.org/2020/formulas/mathematics/high-school/i50b650gqloz2rp7hicfnln43fdkfhe9vn.png)
Standard deviation =
![\sigma = 1.72](https://img.qammunity.org/2020/formulas/mathematics/high-school/udyti1ojsrhvu35dhjxvbxpy7ibhezyi5l.png)
We are supposed to find the proportion of customer purchase amounts between $14.00 and $16.00
P(14<x<16)
Formula :
![z=(x-\mu)/(\sigma)](https://img.qammunity.org/2020/formulas/mathematics/high-school/hq285311c9d1m36eo8c9nqykppzmieuuwe.png)
At x = 14
![z=(14-15.50)/(1.72)](https://img.qammunity.org/2020/formulas/mathematics/high-school/puxj8utec3q6pqza259jiv6l1k93x2mkq3.png)
![z=-0.8720](https://img.qammunity.org/2020/formulas/mathematics/high-school/mdy1zvp1jwlfsdty40wfnet7bz8nhkdggv.png)
Refer the z table for p value
P(x<14)=0.1922
At x = 16
![z=(16-15.50)/(1.72)](https://img.qammunity.org/2020/formulas/mathematics/high-school/m7d3ynhvwfdtpl5nmbzrzswllbn4njseso.png)
![z=0.290](https://img.qammunity.org/2020/formulas/mathematics/high-school/nvdpy97pk7ls1jizjtc4e9oubvtu4o1nfc.png)
Refer the z table for p value
P(x<16)=0.6141
P(14<x<16)=P(x<16)-P(x<14)=0.6141-0.1922=0.42
So, Option C is true
Hence 0.42 is closest to the proportion of customer purchase amounts between $14.00 and $16.00