Question

If the expression ax(2x + y - 5) simplifies to 6x² +3xy - 15x, what is the value of a?

Answer 1

since:
ax(2x + y - 5) = 6x^2 +3xy - 15x,

we should factor X out of the second equation to find out the value of a:
6x^2 + 3xy - 15x =
x(6x + 3y - 15),

Now that we factored X out, to find a, we need to find the other common factor:

(6x + 3y - 15) / (2x + y - 5),

which is 3.

Hence the value of a is 3

Answer 2

a=3

Explanation:

If ax(2x + y - 5) simplifies to 6x² +3xy - 15x

`ax(2x + y - 5)=2ax^2+axy-5ax`

Comparing Coefficients of
`2ax^2+axy-5ax` with
`6x^2 +3xy - 15x`

For
`x^2;` 2a=6===>a=3

xy: a=3

x: -5a=-15==>a=3

Clearly, a=3